Try this argument when AB is r times the length of AM, and when AC is r times the length of AN.

Problem 3

The cheetah can run a total of (105)(7)=735 feet before stopping to rest. The path of the antelope will take it on a path the is closer that 735 feet to the origin between -16 and 12 seconds. Ignoring the negative times because the cheetah is assumed to begin running at t=0 (or greater), the cheetah could catch the antelope at 12 seconds, which means it could wait for 5 seconds before running.

Problem 4

Problem 5

Problem 6

Problem 7

They are describing a 30-60-90 right triangle. The smallest angle is 30 degrees. The other side is whatever it in on this special triangle.

Problem 8

THIS IS A GREAT PROBLEM, LYDIA!

Problem 9

Problem 10

Remember to keep point O inside the square.

Problem 11

The problem asks for a direction. I take this to mean BEARING.

## Table of Contents

## Page 49

## Problem 1

## Problem 2

## Problem 3

Perhaps another card that is 10 inches long an 6 inches wide? Or one that is 5 miles long and 3 miles wide?

## Problem 4

## Problem 5

## Problem 6

The altitudes of one are the perpendicular bisectors of the other

## Problem 7

When I see 9 and 15 in a problem, I am thinking of the triple 9, 12, 15.

## Problem 8

We have done this problem. Here is MY proof...

## Problem 9

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## Problem 10

6cm and 9cm

## Page 50

## Problem 1 and 2

Try this argument when AB is

rtimes the length of AM, and when AC isrtimes the length of AN.## Problem 3

The cheetah can run a total of (105)(7)=735 feet before stopping to rest. The path of the antelope will take it on a path the is closer that 735 feet to the origin between -16 and 12 seconds. Ignoring the negative times because the cheetah is assumed to begin running at t=0 (or greater), the cheetah could catch the antelope at 12 seconds, which means it could wait for 5 seconds before running.

## Problem 4

## Problem 5

## Problem 6

## Problem 7

They are describing a 30-60-90 right triangle. The smallest angle is 30 degrees. The other side is whatever it in on this special triangle.

## Problem 8

THIS IS A GREAT PROBLEM, LYDIA!

## Problem 9

## Problem 10

Remember to keep point O inside the square.

## Problem 11

The problem asks for a direction. I take this to mean BEARING.