1/25/11 Parallelogram Problems

paralleogram weekly challenge
yes, I know I spelled parallelogram wrong in the link but I don't want to make another page.

1/18/11 Connected Midpoints

Parallelogram=

1/11/11 Proving Parallelograms

Part 1

para1.JPG
A+B+A+B= 360
2(A+B)=360, A+B=180
Same Side Supplementary

Part 2

para2.JPG
DCBBAD by SSS (sharing diagonal DB)
∠ABD∠CDB by CPCTC and they are AIA so DC||AB
∠ADB∠CBD by CPCTC and they are AIA so AD||CB

Part 3

para3.JPG
A+B=B+C=C+D=D+A=180
B=D and A=C and opposite angles being congruent means a parallelogram (see 1)

Part 4


para4.JPG

BATDCT by SAS
CBAADC by SAS
∠BAT∠DCT by CPCTC and they're AIA, so DC||AB
∠CBT∠ADT by CPCTC and they're AIA, so BC||AD

Part 5

para5.JPG
∠ABD∠CDB by AIA
ADBCBD by SAS
∠CBD∠ADB by CPCTC and are alternate interior angles so DC||AE and it's a parallelogram

Winter Break/Betty and John Stuff

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Geogebra 3D attempt

Clearly my computer was having problems running Geogebra 3D and doesn't have a microphone, but this is the best I've got. If this had worked, I would have made a 1x1x1 cube, but none of the points actually showed up for me to be able to connect them.


12/2/10 Math Challenge 5- Reflection of a Point

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11/22/10 Math Challenge 4- Transformations

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11/25/10 Math Challenge 3- Sequence

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11/2/10 Math Challenge 2- altitudes, medians, and centers

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Bette H. Portfolio Problem

Widget 3 10/25/10

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Widget 2

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problem 3, pg 3

Make a hexagon that has points at (0,0), (2,1), (3, 3), (2, 5), (0, 4), (-1, 2). Is it equilateral? Prove it. Is it equilangular? How do you know?

This is an equilateral hexagon. If I look at each for the sides as a hypotenuse of a right triangle then I can draw the legs for each. Each triangle has one leg that is 1 unit long and the other leg is 2 units. Using the Pythagorean theorem we can see what each leg will be equal to.
external image latex2png.2.php?z=100&eq=%5Csqrt%7B1%5E2%2B2%5E2%7D%3D%5Csqrt%7B5%7D%20%20

Because I graphed this in geogebra we can see what each angle is and that they're not equal.



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Mathmaticious


So my younger sister showed me this. If you have about 6 and half minutes to spare and want to watch a super nerdy movie, here you go.

This is my page.