A+B+A+B= 360
2(A+B)=360, A+B=180
Same Side Supplementary

Part 2

DCB≅BAD by SSS (sharing diagonal DB)
∠ABD≅∠CDB by CPCTC and they are AIA so DC||AB
∠ADB≅∠CBD by CPCTC and they are AIA so AD||CB

Part 3

A+B=B+C=C+D=D+A=180
B=D and A=C and opposite angles being congruent means a parallelogram (see 1)

Part 4

BAT≅DCT by SAS
CBA≅ADC by SAS
∠BAT≅∠DCT by CPCTC and they're AIA, so DC||AB
∠CBT≅∠ADT by CPCTC and they're AIA, so BC||AD

Part 5

∠ABD≅∠CDB by AIA
ADB≅CBD by SAS
∠CBD≅∠ADB by CPCTC and are alternate interior angles so DC||AE and it's a parallelogram

Winter Break/Betty and John Stuff

Geogebra 3D attempt

Clearly my computer was having problems running Geogebra 3D and doesn't have a microphone, but this is the best I've got. If this had worked, I would have made a 1x1x1 cube, but none of the points actually showed up for me to be able to connect them.

12/2/10 Math Challenge 5- Reflection of a Point

11/22/10 Math Challenge 4- Transformations

11/25/10 Math Challenge 3- Sequence

11/2/10 Math Challenge 2- altitudes, medians, and centers

Make a hexagon that has points at (0,0), (2,1), (3, 3), (2, 5), (0, 4), (-1, 2). Is it equilateral? Prove it. Is it equilangular? How do you know?

This is an equilateral hexagon. If I look at each for the sides as a hypotenuse of a right triangle then I can draw the legs for each. Each triangle has one leg that is 1 unit long and the other leg is 2 units. Using the Pythagorean theorem we can see what each leg will be equal to.

Because I graphed this in geogebra we can see what each angle is and that they're not equal.

Mathmaticious

So my younger sister showed me this. If you have about 6 and half minutes to spare and want to watch a super nerdy movie, here you go.

## 1/25/11 Parallelogram Problems

paralleogram weekly challengeyes, I know I spelled parallelogram wrong in the link but I don't want to make another page.

## 1/18/11 Connected Midpoints

Parallelogram=## 1/11/11 Proving Parallelograms

## Table of Contents

## Part 1

A+B+A+B= 360

2(A+B)=360, A+B=180

Same Side Supplementary

## Part 2

DCB≅BAD by SSS (sharing diagonal DB)

∠ABD≅∠CDB by CPCTC and they are AIA so DC||AB

∠ADB≅∠CBD by CPCTC and they are AIA so AD||CB

## Part 3

A+B=B+C=C+D=D+A=180

B=D and A=C and opposite angles being congruent means a parallelogram (see 1)

## Part 4

CBA≅ADC by SAS

∠BAT≅∠DCT by CPCTC and they're AIA, so DC||AB

∠CBT≅∠ADT by CPCTC and they're AIA, so BC||AD

## Part 5

∠ABD≅∠CDB by AIA

ADB≅CBD by SAS

∠CBD≅∠ADB by CPCTC and are alternate interior angles so DC||AE and it's a parallelogram

## Winter Break/Betty and John Stuff

## Geogebra 3D attempt

Clearly my computer was having problems running Geogebra 3D and doesn't have a microphone, but this is the best I've got. If this had worked, I would have made a 1x1x1 cube, but none of the points actually showed up for me to be able to connect them.## 12/2/10 Math Challenge 5- Reflection of a Point

## 11/22/10 Math Challenge 4- Transformations

## 11/25/10 Math Challenge 3- Sequence

## 11/2/10 Math Challenge 2- altitudes, medians, and centers

## Bette H. Portfolio Problem

## Widget 3 10/25/10

## Widget 2

## problem 3, pg 3

Make a hexagon that has points at (0,0), (2,1), (3, 3), (2, 5), (0, 4), (-1, 2). Is it equilateral? Prove it. Is it equilangular? How do you know?This is an equilateral hexagon. If I look at each for the sides as a hypotenuse of a right triangle then I can draw the legs for each. Each triangle has one leg that is 1 unit long and the other leg is 2 units. Using the Pythagorean theorem we can see what each leg will be equal to.

Because I graphed this in geogebra we can see what each angle is and that they're not equal.

## Mathmaticious

So my younger sister showed me this. If you have about 6 and half minutes to spare and want to watch a super nerdy movie, here you go.

This is my page.